Isomorphism theorems

Correspondence theorem

In group theory, the correspondence theorem (also the lattice theorem, and variously and ambiguously the third and fourth isomorphism theorem) states that if is a normal subgroup of a group , then there exists a bijection from the set of all subgroups of containing , onto the set of all subgroups of the quotient group . The structure of the subgroups of is exactly the same as the structure of the subgroups of containing , with collapsed to the identity element. Specifically, if G is a group,, a normal subgroup of G,, the set of all subgroups A of G that contain N, and, the set of all subgroups of G/N, then there is a bijective map such that for all One further has that if A and B are in then * if and only if ; * if then , where is the index of A in B (the number of cosets bA of A in B); * where is the subgroup of generated by * , and * is a normal subgroup of if and only if is a normal subgroup of . This list is far from exhaustive. In fact, most properties of subgroups are preserved in their images under the bijection onto subgroups of a quotient group. More generally, there is a monotone Galois connection between the lattice of subgroups of (not necessarily containing ) and the lattice of subgroups of : the lower adjoint of a subgroup of is given by and the upper adjoint of a subgroup of is a given by . The associated closure operator on subgroups of is ; the associated kernel operator on subgroups of is the identity. A proof of the correspondence theorem can be found here. Similar results hold for rings, modules, vector spaces, and algebras. (Wikipedia).

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In this video, we practice another example of proving a relation is in fact an equivalence relation. Enjoy! Instagram: https://www.instagram.com/braingainzofficial

From playlist Proofs

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Please Subscribe here, thank you!!! https://goo.gl/JQ8Nys Equivalence Relation on a Group Two Proofs. Given a group G and a subgroup H of G, we prove that the relation x=y if xy^{-1} is in H is an equivalence relation on G. Then cosets are defined and we prove that s_1 = s_2 iff [s_1] = [s

From playlist Abstract Algebra

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From playlist Abstract algebra

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From playlist Abstract Algebra

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From playlist Abstract algebra

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From playlist Geometry

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From playlist Algebraic geometry I: Varieties

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From playlist MIT RES.6-008 Digital Signal Processing, 1975

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From playlist Seminar on Geometric and Modular Representation Theory

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From playlist MIT 18.100A Real Analysis, Fall 2020

Related pages

Bijection | Galois connection | Normal subgroup | Quotient group | Vector space | Isomorphism theorems | Algebra over a field | Kernel operator | Lattice of subgroups | Coset | Generating set of a group | Group theory | Ring (mathematics) | Closure operator | Modular lattice | Module (mathematics) | Group (mathematics) | Identity element